<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-15947468</id><updated>2011-12-31T16:54:09.632-08:00</updated><category term='chess board'/><category term='arrangements'/><category term='counting'/><category term='dominos'/><title type='text'>xyfactor</title><subtitle type='html'>March, Find, Analyze, Siege, Attack and Conquer.</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>54</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-15947468.post-825779105328377469</id><published>2011-08-06T07:28:00.000-07:00</published><updated>2011-08-06T07:29:19.569-07:00</updated><title type='text'>The Monty Hall</title><content type='html'>If you have ever struggled with the Monty Hall, check this out:&lt;br /&gt;&lt;br /&gt;http://www.blog.assignmenthelpsite.com/probability-the-monty-hall-paradox/&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-825779105328377469?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/825779105328377469/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=825779105328377469&amp;isPopup=true' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/825779105328377469'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/825779105328377469'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2011/08/monty-hall.html' title='The Monty Hall'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-1016707149160069851</id><published>2009-12-19T10:05:00.000-08:00</published><updated>2009-12-19T10:10:48.124-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='chess board'/><category scheme='http://www.blogger.com/atom/ns#' term='counting'/><title type='text'>Prepare to square off</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_naprQjEMae8/Sy0WPp_fTFI/AAAAAAAACFI/y6611smAod0/s1600-h/Chessboard_1000.gif"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 116px; height: 116px;" src="http://1.bp.blogspot.com/_naprQjEMae8/Sy0WPp_fTFI/AAAAAAAACFI/y6611smAod0/s200/Chessboard_1000.gif" alt="" id="BLOGGER_PHOTO_ID_5417010385022569554" border="0" /&gt;&lt;/a&gt;Consider an 8x8 chess board as shown in the adjacent figure. How many squares can you count without repetition?&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Now consider the infinite chess board shown in the next figure. What is the inverse of the &lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_naprQjEMae8/Sy0WVfI7yPI/AAAAAAAACFQ/dHGWUHiBjkk/s1600-h/chesssph.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 109px; height: 109px;" src="http://4.bp.blogspot.com/_naprQjEMae8/Sy0WVfI7yPI/AAAAAAAACFQ/dHGWUHiBjkk/s200/chesssph.jpg" alt="" id="BLOGGER_PHOTO_ID_5417010485188610290" border="0" /&gt;&lt;/a&gt;sum of the squares of all the distinct areas of squares that can formed from this board? What is the inverse of the sum of squares of all the square areas that can be formed from this board?&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_naprQjEMae8/Sy0WVfI7yPI/AAAAAAAACFQ/dHGWUHiBjkk/s1600-h/chesssph.jpg"&gt;&lt;br /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-1016707149160069851?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/1016707149160069851/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=1016707149160069851&amp;isPopup=true' title='5 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/1016707149160069851'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/1016707149160069851'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2009/12/prepare-to-square-off.html' title='Prepare to square off'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_naprQjEMae8/Sy0WPp_fTFI/AAAAAAAACFI/y6611smAod0/s72-c/Chessboard_1000.gif' height='72' width='72'/><thr:total>5</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-7393581412131755594</id><published>2009-12-19T09:51:00.000-08:00</published><updated>2009-12-19T10:05:03.259-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='arrangements'/><category scheme='http://www.blogger.com/atom/ns#' term='dominos'/><title type='text'>Playing with dominoes - II</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_naprQjEMae8/Sy0U6Uvac6I/AAAAAAAACFA/rHf3Fkb-25g/s1600-h/MutilatedChessboardButton200.gif"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 200px; height: 200px;" src="http://3.bp.blogspot.com/_naprQjEMae8/Sy0U6Uvac6I/AAAAAAAACFA/rHf3Fkb-25g/s200/MutilatedChessboardButton200.gif" alt="" id="BLOGGER_PHOTO_ID_5417008919029117858" border="0" /&gt;&lt;/a&gt;This one is often attributed to &lt;a href="http://en.wikipedia.org/wiki/Martin_Gardner"&gt;Martin Gardner&lt;/a&gt;.&lt;br /&gt;&lt;br /&gt;How many &lt;a href="http://en.wikipedia.org/wiki/Dominoes"&gt;dominoes&lt;/a&gt; would you require to fill up a 8x8 chess board?&lt;br /&gt;&lt;br /&gt;Now, let us give vent to the suppressed child in us, and mangle the chess board by removing the opposite corner squares (see picture). How many dominoes would you require now?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-7393581412131755594?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/7393581412131755594/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=7393581412131755594&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/7393581412131755594'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/7393581412131755594'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2009/12/playing-with-dominoes-ii.html' title='Playing with dominoes - II'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_naprQjEMae8/Sy0U6Uvac6I/AAAAAAAACFA/rHf3Fkb-25g/s72-c/MutilatedChessboardButton200.gif' height='72' width='72'/><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-3142014600459025084</id><published>2009-12-18T08:50:00.000-08:00</published><updated>2009-12-18T10:21:44.008-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='arrangements'/><category scheme='http://www.blogger.com/atom/ns#' term='dominos'/><title type='text'>Playing with dominoes</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_naprQjEMae8/SyvHTZxRqTI/AAAAAAAACEw/MLPBka1Peq4/s1600-h/domino.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 164px; height: 219px;" src="http://4.bp.blogspot.com/_naprQjEMae8/SyvHTZxRqTI/AAAAAAAACEw/MLPBka1Peq4/s320/domino.jpg" alt="" id="BLOGGER_PHOTO_ID_5416642112992160050" border="0" /&gt;&lt;/a&gt;A domino is a 2x1 piece of rectangle (see picture). Now consider a rectangular area of size nx2. The question is simple: given a large number of identical dominoes, how many different ways of arrangements of the 2x1 dominoes into the nx2 area are possible? Assume all the dominoes are identical. Note that as always, key ideas are more important in this blog than complete solutions.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-3142014600459025084?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/3142014600459025084/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=3142014600459025084&amp;isPopup=true' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/3142014600459025084'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/3142014600459025084'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2009/12/playing-with-dominoes.html' title='Playing with dominoes'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_naprQjEMae8/SyvHTZxRqTI/AAAAAAAACEw/MLPBka1Peq4/s72-c/domino.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-3150857643657109865</id><published>2008-06-19T22:56:00.000-07:00</published><updated>2008-06-19T22:59:24.625-07:00</updated><title type='text'>DARPA mathematical challenges</title><content type='html'>Alright dudes. Its time to show you some real $$$. Check out the DARPA mathematical challenge:&lt;br /&gt;&lt;br /&gt;https://www.fbo.gov/utils/view?id=4a43eacdb1c247bc9809e581987b8f31&lt;br /&gt;&lt;br /&gt;As the one who told you about the problems, I get a 15% cut. Thanks.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-3150857643657109865?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/3150857643657109865/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=3150857643657109865&amp;isPopup=true' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/3150857643657109865'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/3150857643657109865'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2008/06/darpa-mathematical-challenges.html' title='DARPA mathematical challenges'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-6901930073513073758</id><published>2008-02-22T14:10:00.000-08:00</published><updated>2008-02-22T14:19:50.499-08:00</updated><title type='text'>People on a plane!</title><content type='html'>(Motivated by snakes on a plane) Here are two of the standard people on plane problem just to get things rolling again:&lt;br /&gt;1) There are (say) 100 seats on a plane and since people with disabilities board first, the blind person boards first. Let us say this isnt Southwest and that each person is assigned a fixed seat (even the blind person is assigned a seat) and if his seat is occupied, he will sit in any seat that is free. Let us further say that the blind person picks his seat randomly of all the ones on the plane. The question is: What is the probability that the last (100th) person gets to sit in his assigned seat?&lt;br /&gt;2) (Easier) Say there are n seats and n people. What are the number of ways in which each person sits in a different seat?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-6901930073513073758?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/6901930073513073758/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=6901930073513073758&amp;isPopup=true' title='355 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/6901930073513073758'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/6901930073513073758'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2008/02/people-on-plane.html' title='People on a plane!'/><author><name>Macaulay</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>355</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-533177317038484115</id><published>2007-11-13T08:59:00.000-08:00</published><updated>2007-11-13T09:02:54.596-08:00</updated><title type='text'>Queens!</title><content type='html'>Apologies for the long absence. Lets try to solve the problem of the queens. This one is derived from the question asked by Vichu. &lt;br /&gt;&lt;br /&gt;We know that the problem of placing 8 queens on a 8x8 chessboard without any queen cutting any other is quite simple. The question to be solved now is: How many such unique arrangements are possible?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-533177317038484115?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/533177317038484115/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=533177317038484115&amp;isPopup=true' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/533177317038484115'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/533177317038484115'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2007/11/queens.html' title='Queens!'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-5043806409819362219</id><published>2007-04-26T19:13:00.000-07:00</published><updated>2007-04-26T19:14:20.667-07:00</updated><title type='text'>Bit by Bit...</title><content type='html'>What is the smartest way of counting the number of bits in a byte? (psuedocode please)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-5043806409819362219?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/5043806409819362219/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=5043806409819362219&amp;isPopup=true' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/5043806409819362219'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/5043806409819362219'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2007/04/bit-by-bit.html' title='Bit by Bit...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-1045208269699588805</id><published>2007-04-25T19:20:00.000-07:00</published><updated>2007-04-27T16:51:57.059-07:00</updated><title type='text'>Catching a cop</title><content type='html'>Say X has not received a speeding ticket in the last year.&lt;br /&gt;&lt;br /&gt;Do the odds that X gets caught speeding tomorrow increase because the event has not occurred during the last year?&lt;br /&gt;&lt;br /&gt;Alternately, can A confidently speed tomorrow if he received a ticket today?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-1045208269699588805?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/1045208269699588805/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=1045208269699588805&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/1045208269699588805'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/1045208269699588805'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2007/04/catching-cop.html' title='Catching a cop'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-3955961767744926679</id><published>2007-03-16T19:46:00.000-07:00</published><updated>2007-03-16T19:49:49.278-07:00</updated><title type='text'>Jump or Stay?</title><content type='html'>I have this seemingly innocous habit of taking the ladder up to my attic window.&lt;br /&gt;&lt;br /&gt;However, on this sunny summer afternoon things take an unpleasant turn. My ladder starts falling away from the wall just as I am about to step into my window. Would you recommend that I stay with the ladder and fall to the ground, or should I jump off the ladder?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-3955961767744926679?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/3955961767744926679/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=3955961767744926679&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/3955961767744926679'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/3955961767744926679'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2007/03/jump-or-stay.html' title='Jump or Stay?'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-115986582925891335</id><published>2006-10-03T01:50:00.000-07:00</published><updated>2006-10-03T01:57:38.050-07:00</updated><title type='text'>An Uncomplicated Kill</title><content type='html'>&lt;span style="font-family: arial;"&gt;On a top secret assignment in &lt;/span&gt;&lt;a style="font-family: arial;" href="http://en.wikipedia.org/wiki/Azerbaijan" title="Azerbaijan"&gt;Azerbaijan&lt;/a&gt;&lt;span style="font-family: arial;"&gt;, you and your partners are rather bored, and Vodka is in short supply. Being the daredevils that you all are, you decide to play a modified game of Russian roulette to eliminate one of you. A six shooter revolver is purchased from the neighborhood arms dealer and three bullets are loaded in a row in three consecutive chambers. The barrel is spun only once. Then, each player points the gun at their head and pulls the trigger. The game stops when one person is dead.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family: arial;"&gt;Would you rather be first or second to shoot?&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-115986582925891335?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/115986582925891335/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=115986582925891335&amp;isPopup=true' title='28 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115986582925891335'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115986582925891335'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/10/uncomplicated-kill.html' title='An Uncomplicated Kill'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>28</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-115949835015047951</id><published>2006-09-28T19:51:00.000-07:00</published><updated>2006-09-28T19:53:36.580-07:00</updated><title type='text'>Two real problems</title><content type='html'>&lt;span style="font-family:arial;"&gt;  I pick two reals &lt;/span&gt;&lt;em style="font-family: arial;"&gt;x&lt;/em&gt;&lt;span style="font-family:arial;"&gt; and &lt;/span&gt;&lt;em style="font-family: arial;"&gt;y&lt;/em&gt;&lt;span style="font-family:arial;"&gt;.  I show one of them to you randomly by tossing a fair coin.  You have to tell me if the number you see  is the larger or the smaller of the two.  How do you do this so that for any  choice of &lt;/span&gt;&lt;em style="font-family: arial;"&gt;x&lt;/em&gt;&lt;span style="font-family:arial;"&gt; and &lt;/span&gt;&lt;em style="font-family: arial;"&gt;y&lt;/em&gt;&lt;span style="font-family:arial;"&gt;, the probability that you are  correct is strictly larger than .5?  &lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;On a sold out flight, 100 people line up to board the plane. The first passenger in the line has lost his boarding pass, but was allowed in, regardless. He takes a random seat. Each subsequent passenger takes his or her assigned seat if available, or a random unoccupied seat, otherwise. What is the probability that the last passenger to board the plane finds his seat unoccupied? &lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-115949835015047951?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/115949835015047951/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=115949835015047951&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115949835015047951'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115949835015047951'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/09/two-real-problems.html' title='Two real problems'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-115941579400369872</id><published>2006-09-27T20:54:00.000-07:00</published><updated>2006-09-27T21:03:27.023-07:00</updated><title type='text'>Stringer Verlag</title><content type='html'>&lt;span style="font-family: arial;font-family:arial;" &gt;What is the longest string you can make using only C's and G's within the following constraints:&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family: arial;font-family:arial;" &gt;1. No GG can occur within the string,&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family: arial;font-family:arial;" &gt;2. No sub-string can repeat itself 3 times consecutively eg: CGCGCG is not allowed.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family: arial;font-family:arial;" &gt;Why?&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-115941579400369872?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/115941579400369872/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=115941579400369872&amp;isPopup=true' title='8 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115941579400369872'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115941579400369872'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/09/stringer-verlag.html' title='Stringer Verlag'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>8</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-115907089018860744</id><published>2006-09-23T21:05:00.000-07:00</published><updated>2006-09-24T09:05:24.743-07:00</updated><title type='text'>Suspension bridges</title><content type='html'>&lt;span style="font-family:arial;"&gt;You must have seen the Golden Gate bridge or one of the other suspension bridges during your travels. What curve do the cables follow?&lt;br /&gt;&lt;br /&gt;Admittedly, this is a bit mathematical. Hence, I shall abstain from giving points if someone complains. Otherwise, 1 point! &lt;/span&gt;&lt;br /&gt;&lt;p&gt;&lt;span style="font-family:arial;"&gt;It gets somewhat interesting after you solve the problem. Shown below is a stolen picture of the chelsea bridge. In red diamond symbols are second order polynomial fits to the main cable. I simply digitized the middle cable and fitted it in matlab. While the good fit makes it very tempting to conclude that its a proof for a parabolic curve, the catenoid can also be series expanded to a parabola accurate to 4th order! Any small error in curve fit could push it this way or that. So, I guess the fitting does not say anything useful other than the fact that the cable is roughly a parabola.&lt;/p&gt;&lt;/span&gt;&lt;img style="DISPLAY: block; MARGIN: 0px auto 10px; CURSOR: hand; TEXT-ALIGN: center" alt="" src="http://photos1.blogger.com/blogger/2436/723/400/bridgeinterp.0.jpg" border="0" /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;&lt;br /&gt;ps: Check out Manoj's angle trisection comments at &lt;a href="http://xyfactor.blogspot.com/2006/05/trisect-angle.html"&gt;http://xyfactor.blogspot.com/2006/05/trisect-angle.html&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;&lt;/span&gt;&lt;span style="font-family:arial;"&gt;&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-115907089018860744?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/115907089018860744/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=115907089018860744&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115907089018860744'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115907089018860744'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/09/suspension-bridges.html' title='Suspension bridges'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-115325391252194982</id><published>2006-07-18T13:11:00.000-07:00</published><updated>2006-09-23T21:13:17.790-07:00</updated><title type='text'>Angles of a Quadrilateral</title><content type='html'>&lt;span style="font-weight: bold; font-family: arial;"&gt;Simple Question&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family: arial;"&gt;a) What is the minimum number of acute angles in a &lt;/span&gt;&lt;span style="font-weight: bold; font-family: arial;"&gt;convex &lt;/span&gt;&lt;span style="font-family: arial;"&gt;quadrilateral? Prove.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family: arial;font-size:85%;" &gt;That may be too easy. So, I'll give a point to (or split point between) the most creative and entertaining answer(s).&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family: arial;"&gt;b) What is the minimum number of acute angles in a &lt;/span&gt;&lt;span style="font-weight: bold; font-family: arial;"&gt;concave&lt;/span&gt;&lt;span style="font-family: arial;"&gt; quadrilateral? Prove.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold; font-family: arial;"&gt;&lt;span style="font-size:85%;"&gt;Clarification:&lt;br /&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="font-family: arial;font-size:85%;" &gt;By &lt;/span&gt;&lt;span style="font-weight: bold; font-family: arial;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span style="font-weight: bold;"&gt;acute, &lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="font-family: arial;font-size:85%;" &gt;I mean angles that are 90 deg or lower. &lt;span style="font-weight: bold;"&gt;Acute &lt;/span&gt;= &lt;span style="font-weight: bold;"&gt;Non-obtuse&lt;/span&gt;.&lt;/span&gt;&lt;span style="font-weight: bold; font-family: arial;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span style="font-weight: bold;"&gt;&lt;/span&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-115325391252194982?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/115325391252194982/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=115325391252194982&amp;isPopup=true' title='9 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115325391252194982'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/115325391252194982'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/07/angles-of-quadrilateral.html' title='Angles of a Quadrilateral'/><author><name>Sisyphus</name><uri>http://www.blogger.com/profile/18176716289283309305</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>9</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114844079047787600</id><published>2006-05-23T20:15:00.000-07:00</published><updated>2006-09-23T21:13:35.876-07:00</updated><title type='text'>Trisect an Angle</title><content type='html'>&lt;span style="font-family: arial;"&gt;Ok, here is a slightly more interesting one to further the progression of puzzles we have had here. Given a pencil and a straight edge, trisect a given (acute) angle. This is a classic geometry problem that has resisted the advances of the scale toting geometers for quite some time. Of late, a new and interesting way has been proposed to solve this problem which approaches geometry in a very nice and innovative way. I will post a hint if you guys have much trouble (though going by the other problems I have posted, this seems unlikely..)&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family: arial;"&gt;Macaulay&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114844079047787600?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114844079047787600/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114844079047787600&amp;isPopup=true' title='10 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114844079047787600'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114844079047787600'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/05/trisect-angle.html' title='Trisect an Angle'/><author><name>Macaulay</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>10</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114841750071067680</id><published>2006-05-23T13:51:00.000-07:00</published><updated>2006-05-23T20:41:22.683-07:00</updated><title type='text'>A deadly gamble</title><content type='html'>You are sentenced to be hanged by the neck till death. Arnie (the governor) agrees to pardon you if you can solve this puzzle for him (since he is thickheaded as we all know). You are given a deck of 52 cards in a dark room (so you cannot see the cards). You are told from the get go that exactly 17 of these cards are face up (and the tactile feel of the cards is the same on both sides). The question then is to split the deck into two stacks which have the same number of face up cards.&lt;br /&gt;&lt;br /&gt;- Satish&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114841750071067680?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114841750071067680/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114841750071067680&amp;isPopup=true' title='8 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114841750071067680'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114841750071067680'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/05/deadly-gamble.html' title='A deadly gamble'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>8</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114840368958672137</id><published>2006-05-23T10:01:00.000-07:00</published><updated>2006-05-23T10:01:29.603-07:00</updated><title type='text'>Fair toss</title><content type='html'>As you know, most coins are not perfect (i.e. the probability of heads is not equal to the probability of tails). So here is a simple probability exercise. Given a biased coin with P(heads)=p (obviously p is not a half), how would you simulate a fair coin?&lt;br /&gt;&lt;br /&gt;-Satish&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114840368958672137?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114840368958672137/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114840368958672137&amp;isPopup=true' title='15 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114840368958672137'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114840368958672137'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/05/fair-toss.html' title='Fair toss'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>15</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114835930573577990</id><published>2006-05-22T21:34:00.000-07:00</published><updated>2006-05-23T12:17:24.753-07:00</updated><title type='text'>Call me!</title><content type='html'>&lt;div style="text-align: justify;"&gt;&lt;span style="font-style: italic; font-weight: bold;"&gt;My phone number has all the integers from 1 to 7 except one number. The missing digit is the number of times the 1's appear in the number.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-style: italic; font-weight: bold;"&gt;The 1's always immediately follow the 2's, and are, very conveniently, equispaced. &lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;&lt;span style="font-weight: bold;"&gt;If you remove the 1's and the 2's, the rest of the digits form a number that is a product of three prime numbers. The first prime has a single digit, the second has two digits and the third has three. &lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;&lt;span style="font-weight: bold;"&gt;Find it!&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;&lt;/span&gt;&lt;span style="font-style: italic;"&gt;ps: Don't friggin look at your address book... &lt;/span&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;pps: If you do figure it out, you'd better give me a holler, feller. :)&lt;br /&gt;&lt;br /&gt;ppps: Its a US number with 10 digits.&lt;br /&gt;&lt;/span&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114835930573577990?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114835930573577990/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114835930573577990&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114835930573577990'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114835930573577990'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/05/call-me.html' title='Call me!'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114809716915915210</id><published>2006-05-19T20:50:00.000-07:00</published><updated>2006-05-19T20:52:49.173-07:00</updated><title type='text'>Stability of a train</title><content type='html'>Ok, this one does not carry any points. It is only to feed your intellect; maybe even that little kid that lurks inside you and thinks about a train once in a while. With fascination and passion.&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;What keeps a train on the track?! &lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114809716915915210?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114809716915915210/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114809716915915210&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114809716915915210'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114809716915915210'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/05/stability-of-train.html' title='Stability of a train'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114444015084114369</id><published>2006-04-07T13:00:00.000-07:00</published><updated>2006-04-12T22:18:29.353-07:00</updated><title type='text'>Sylvester's theorem</title><content type='html'>There are a finite number of points on a plane. They are situated such that any line through any 2 of the points have at least one other of these points lying on it. Prove that all points are collinear.&lt;br /&gt;&lt;br /&gt;From prior experience of hearing proof attempts, if you are giving a proof by induction, please consider your proof carefully before taking the effort to type it up.&lt;br /&gt;&lt;br /&gt;General background: Sylvester was the first person to prove this, but his proof was a 7 page long proof! However, the current best known proof is very elegant.&lt;br /&gt;&lt;br /&gt;~Grenade&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114444015084114369?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114444015084114369/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114444015084114369&amp;isPopup=true' title='13 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114444015084114369'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114444015084114369'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/04/sylvesters-theorem.html' title='Sylvester&apos;s theorem'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>13</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114442186386907071</id><published>2006-04-07T07:53:00.000-07:00</published><updated>2006-04-07T07:57:43.870-07:00</updated><title type='text'>Sudoku</title><content type='html'>You must definitely know about sudoku,which has become a runaway hit all over the world.Exactly how many sudoku puzzles can be constructed?&lt;br /&gt;&lt;br /&gt;~Sai&lt;br /&gt;&lt;br /&gt;&lt;a href="http://en.wikipedia.org/wiki/Sudoku"&gt;http://en.wikipedia.org/wiki/Sudoku&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114442186386907071?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114442186386907071/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114442186386907071&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114442186386907071'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114442186386907071'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/04/sudoku.html' title='Sudoku'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114442158783924962</id><published>2006-04-07T07:51:00.000-07:00</published><updated>2006-04-07T07:53:07.960-07:00</updated><title type='text'>Angles without the angles...</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/2436/723/1600/puzzle1.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://photos1.blogger.com/blogger/2436/723/400/puzzle1.jpg" alt="" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/2436/723/1600/puzzle1.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://photos1.blogger.com/blogger/2436/723/400/puzzle1.jpg" alt="" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;I saw this in a Martin Gardner book a while ago. Shown in the figure are 3 squares, and 3 angles in the bottom left. Prove, without any trigonometry (or equivalent), that the sum of the two smaller angles equals the largest.&lt;br /&gt;&lt;br /&gt;~ Grenade&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114442158783924962?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114442158783924962/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114442158783924962&amp;isPopup=true' title='8 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114442158783924962'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114442158783924962'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/04/angles-without-angles.html' title='Angles without the angles...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>8</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114400546048777307</id><published>2006-04-02T12:17:00.000-07:00</published><updated>2006-04-02T12:20:06.340-07:00</updated><title type='text'>Seven Eleven</title><content type='html'>Given a seven-digit number,whose digits add up to 59.Find the probability that the number is divisible by 11.&lt;br /&gt;&lt;br /&gt;PS: Would this qualify as a puzzle?? And sorry for any bitter exam-related memories I may have inadvertently invoked in some of you...:)&lt;br /&gt;&lt;br /&gt;~sai&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114400546048777307?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114400546048777307/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114400546048777307&amp;isPopup=true' title='13 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114400546048777307'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114400546048777307'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/04/seven-eleven.html' title='Seven Eleven'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>13</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114386523813827613</id><published>2006-03-31T20:19:00.000-08:00</published><updated>2006-04-07T14:50:26.783-07:00</updated><title type='text'>Hydrocarbon based bipeds - Solve this!</title><content type='html'>&lt;a href="profile/7689492" rel="nofollow" onclick="window.open(this.href);return false;" class="comment-poster-name"&gt;&lt;/a&gt;In a hasty attempt to remove comments about me from the top of the page, I pose this puzzle(?)based on something I did about 10 years ago: &lt;p&gt;A lot of us may know/remember that the bond angle of methane - CH_4 is approximately 109 degrees 28 minutes. This is created by 4 H atoms in 3d space repelling each other to produce a symmetric arrangement about the central C atom. Now tell me what is the bond angle of a hypothetical CH_(n +1)molecule in n dimensional space?&lt;br /&gt;(Note for those who don't like chemistry: The chemical notation is used only to simplify description of what I would have to otherwise state as the angle subtended by the edge of a regular n dimensional hypertetrahedron at its center).&lt;br /&gt;&lt;/p&gt; &lt;p&gt;~ grenade&lt;br /&gt;---------------------------------------------------------------------------------&lt;br /&gt;In general, a hyper- prefix stands for a something with a generalised number of dimensions. ie a 2 dimensional (hyper)cube would be a square. A 3 dimensional (hyper)cube is a cube. The hyper prefix, however begins to become non-trivial when go into a larger number of dimensions. Just as a 3D cube is made by using 2 parallel 2D cubes that are offset in the 3rd D, and then by joining pairs of corresponding vertices by edges, the 4D hypercube is made by 2 parallel 3D ubes that are offset along an imaginary 4th axis (that's perpendicular to x, y and z) and then joining the corresponding vertices of the cubes.&lt;br /&gt;&lt;/p&gt;&lt;br /&gt;A regular tetrahedron is a little more simple. In n dimensions, the regular n-hypertetrahedron consists of n+1 points that are equidistant from each other. So a 3D regular tetrahedron is a normal regular tetrahedron. A 2D regular tetrahedron is an equilateral triangle. A 1D regular tetrahedrom is a line segment (which is also a 1D cube). A 0D tetrahedron is a point (which is pretty much a 0D anything - well, anything that's not nothing, anyway).&lt;br /&gt;&lt;br /&gt;I am afraid I am unable to give a better explanation within the confines of a blog editor, but I would recommend reading Martin Gardner's Mathematical circus, one of whose chapters has an introduction to hyperspaces.&lt;br /&gt;~grenade&lt;br /&gt;---------------------------------------------------------------------------------&lt;br /&gt;From the lack of responses, I assume that the jump into hyperspace was made too far. So I will pose a simpler(?) question from the aforementioned Martin Gardner book:&lt;br /&gt;Imagine an infinite checkerboard. Circumscribe the black squares with circles. These circles will intersect the white squares, and it is a matter of simple arithmetic to check what fraction of the white squares' areas are left unoccupied by the circles (or discs, if you would prefer).&lt;br /&gt;&lt;br /&gt;Now extend it to 3D. We have an infinite "3d chessboard" where black and white cubes repeat alternatingly in all 3 directions. The black cubes are circumscribed by spheres whcih overlap the white cubes. It is a pretty hard exercise to calculate what volumes of the white hypercubes are left unoverlapped by the spheres, because the spheres intersect each other, and the math becomes messy.&lt;br /&gt;&lt;br /&gt;My question is this: In 4D, what fraction of the hypervolume of the white hypercubes is left unoverlapped by the hyperspheres circumscribing the black hypercubes in an infinite 4d chessboard (alternating black and white 4d hypercubes along 4 mutually orthogonal directions)?&lt;br /&gt;&lt;br /&gt;How about n-dimensions? n&gt;4?&lt;br /&gt;~grenade&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114386523813827613?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114386523813827613/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114386523813827613&amp;isPopup=true' title='12 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114386523813827613'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114386523813827613'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/03/hydrocarbon-based-bipeds-solve-this.html' title='Hydrocarbon based bipeds - Solve this!'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>12</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114080525205818818</id><published>2006-02-24T10:09:00.000-08:00</published><updated>2006-02-28T10:15:57.466-08:00</updated><title type='text'>A construction problem...</title><content type='html'>The ancient temples in the kindgom of Pantheia are built with dimensions that are exact multiples of a unitum. Further, the dimensions of each room must be &lt;span style="font-weight: bold;"&gt;all&lt;/span&gt; different. For example, a temple with rooms of dimensions 5x11 and 13x5 is not allowed and neither is one with a square room.&lt;br /&gt;&lt;br /&gt;You are the architect and are asked to build a new rectangular temple at the top of the flat topped mountain, Polypheme with atleast 2 rooms. The limited space on the mountain top means that you have to minimize the area of the temple. What is the temple with the smallest area that you can construct under the above constraints?&lt;br /&gt;&lt;br /&gt;Explan clearly.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114080525205818818?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114080525205818818/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114080525205818818&amp;isPopup=true' title='18 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114080525205818818'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114080525205818818'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/02/construction-problem.html' title='A construction problem...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>18</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-114006095204750798</id><published>2006-02-15T19:31:00.000-08:00</published><updated>2006-02-15T19:35:52.140-08:00</updated><title type='text'>Unfork your way through...</title><content type='html'>Two tribes live in a jungle - the truth tellers (who always speak the truth) and the liars (who always lie). A traveler is walking along a path when he comes to an unmarked fork in the road. One path goes to his hometown. And he does not know which. Just then, a native comes along belonging to one of the two tribes mentioned above. What is one question he could pose to the native so that he finds his way home? (0.5 points)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-114006095204750798?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/114006095204750798/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=114006095204750798&amp;isPopup=true' title='16 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114006095204750798'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/114006095204750798'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/02/unfork-your-way-through.html' title='Unfork your way through...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>16</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113815366953364155</id><published>2006-01-24T17:38:00.000-08:00</published><updated>2006-01-24T17:47:49.533-08:00</updated><title type='text'>Food for thought...</title><content type='html'>A crazy (suspected Brit?) explorer wishes to cross a desert on foot. It takes six days to cross the desert. One man can carry enough food for only 4 days. Under this scenario, using trial and error, you can find the fewest number of men required so that the explorer crosses the desert and the coolie(s) return(s) alive. What is this minimum number? (0.1 point - sorry, this is easy!)&lt;br /&gt;&lt;br /&gt;The real question (1.0 point) is to find an elegant logic to generalize this problem. That is, if it takes N days for an explorer to cross the desert and each man can carry enough food for k days, what algorithm should be employed to attain the objective?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113815366953364155?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113815366953364155/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113815366953364155&amp;isPopup=true' title='20 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113815366953364155'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113815366953364155'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/01/food-for-thought.html' title='Food for thought...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>20</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113774647180289129</id><published>2006-01-20T00:38:00.000-08:00</published><updated>2006-01-24T17:48:18.493-08:00</updated><title type='text'>Does it ring a bell?</title><content type='html'>Can a wind chime be viewed from an angle so that the tips of the chime rods fall in a single plane? (Non-trivial solutions only allowed)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113774647180289129?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113774647180289129/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113774647180289129&amp;isPopup=true' title='9 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113774647180289129'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113774647180289129'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/01/does-it-ring-bell.html' title='Does it ring a bell?'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>9</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113717608809293340</id><published>2006-01-13T10:11:00.000-08:00</published><updated>2006-01-13T10:14:48.093-08:00</updated><title type='text'>Even-steven</title><content type='html'>Twelve iron canon balls have the same weight, but for one that has a different weight. Find the odd ball, using only three weighings on a balance scale and determine whether it is light or heavy.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113717608809293340?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113717608809293340/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113717608809293340&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113717608809293340'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113717608809293340'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/01/even-steven.html' title='Even-steven'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113717586812759935</id><published>2006-01-13T10:08:00.000-08:00</published><updated>2006-01-20T07:38:50.733-08:00</updated><title type='text'>Vowel talk...</title><content type='html'>Find three English words that have the vowels a,e,i,o and u in order.&lt;br /&gt;&lt;br /&gt;0.2 points for each word upto a maximum of 1.0. No googling allowed.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113717586812759935?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113717586812759935/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113717586812759935&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113717586812759935'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113717586812759935'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/01/vowel-talk.html' title='Vowel talk...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113642313028758042</id><published>2006-01-04T17:02:00.000-08:00</published><updated>2006-01-04T22:04:39.286-08:00</updated><title type='text'>The attack of the academics...</title><content type='html'>Here is a rather academic problem which nevertheless reduces to some other interesting problems:&lt;br /&gt;&lt;br /&gt;What is the expected value of the maximum of N random variables, each of which is between 0 and 1?&lt;br /&gt;&lt;br /&gt;What is the expected maximum value of 2 variables under the constraint x+y=1?&lt;br /&gt;&lt;br /&gt;If you have figured each of these out, you have passed the qualifying round for this month's IBM ponder this!&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113642313028758042?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113642313028758042/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113642313028758042&amp;isPopup=true' title='16 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113642313028758042'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113642313028758042'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2006/01/attack-of-academics.html' title='The attack of the academics...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>16</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113588453592141339</id><published>2005-12-29T11:21:00.000-08:00</published><updated>2005-12-29T11:30:20.530-08:00</updated><title type='text'>The cook in the noodle shop</title><content type='html'>After a tiresome day boiling vegetables, the cook sits down in the corner of his dingy kitchen for dinner. As is his quaint habit, he puts exactly 100 noodles in his soup and begins his ritual:&lt;br /&gt;&lt;br /&gt;He extracts two noodle ends from the bowl, ties a knot and slips it back into the soup. He repeats this 100 times until all the ends are tied. Now, he reaches his hand into the soup.&lt;br /&gt;&lt;br /&gt;What is the probability that he would extract a garland containing all the 100 noodles?&lt;br /&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;credits: tuku&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113588453592141339?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113588453592141339/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113588453592141339&amp;isPopup=true' title='12 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113588453592141339'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113588453592141339'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/12/cook-in-noodle-shop.html' title='The cook in the noodle shop'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>12</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113523451029338633</id><published>2005-12-21T22:53:00.000-08:00</published><updated>2005-12-21T22:55:10.326-08:00</updated><title type='text'>A number born of 3 digits</title><content type='html'>ok, all this fence planning has prompted me to offer a simpler puzzle for those who would like to relax a little: what is the largest number that can be created out of 3 digits and any operators ? no googling please.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113523451029338633?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113523451029338633/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113523451029338633&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113523451029338633'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113523451029338633'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/12/number-born-of-3-digits.html' title='A number born of 3 digits'/><author><name>lenscrafter</name><uri>http://www.blogger.com/profile/00876833131731273986</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='17' src='http://www.glue.umd.edu/~arvindc/lenscrafterblog/eyeicon.jpg'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113488273770658734</id><published>2005-12-17T21:04:00.000-08:00</published><updated>2006-01-03T17:20:38.333-08:00</updated><title type='text'>Fencing without fights...</title><content type='html'>A farmer, one Mr. S, owns an uncultivated square field of green grass surrounded on all sides by pastures owned by his friends. Annoyingly for Mr. S, the cows grazing in the surrounding pastures often travel across Mr. S 's land to one of the other pastures.&lt;br /&gt;&lt;br /&gt;Mr. S decides to stop this nonsense and considers isolating his field with a fence, but then a brainwave strikes him: "Instead of making the field impassible for these cows, what if I simply fool them into thinking it's impassible? I could build the fencing in such a way that they cannot see the other pastures and therefore won't try to walk across my field!"&lt;br /&gt;&lt;br /&gt;At first, Mr. S considers building two fences in the shape of an 'X' across his field, which would block the view from any side of the square field to any other, thereby preventing the cows from trying to cross while saving on the amount of fencing needed.&lt;br /&gt;&lt;br /&gt;     But then he realizes that he could accomplish the same goal with even less fencing...&lt;br /&gt;&lt;br /&gt;Can you determine the minimum amount of fencing required to block the view from any side of Mr. S's field to any of the other three sides?&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;This one is a big guy and carries 2.0 points! &lt;/span&gt;&lt;span style="font-style: italic;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113488273770658734?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113488273770658734/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113488273770658734&amp;isPopup=true' title='20 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113488273770658734'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113488273770658734'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/12/fencing-without-fights.html' title='Fencing without fights...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>20</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113458625118544287</id><published>2005-12-14T10:41:00.000-08:00</published><updated>2005-12-16T08:23:40.783-08:00</updated><title type='text'>Can you sum me out?</title><content type='html'>The rules of this game are simple:&lt;br /&gt;&lt;br /&gt;1. Numbers 1, 2, 3... 9 are arranged in a row. At every turn, each player chooses a number and adds it to all the previously chosen numbers.&lt;br /&gt;2. The player who gets to 15, by summing any 3 of his chosen numbers, wins.&lt;br /&gt;&lt;br /&gt;For example&lt;br /&gt;&lt;br /&gt;Turn 1:&lt;br /&gt;Me   5&lt;br /&gt;You  9&lt;br /&gt;Me   8&lt;br /&gt;You  2&lt;br /&gt;Me   3&lt;br /&gt;You  4&lt;br /&gt;&lt;br /&gt;You win (9+2+4=15)!&lt;br /&gt;&lt;br /&gt;If you win, I will give you triple the money. If I win, I keep your money. If neither wins, the pot is split. To give you the advantage of winning, I will let you choose your turn - that is, you can choose to play first or second!&lt;br /&gt;&lt;br /&gt;Would you want to play with me?&lt;br /&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;Clue: This problem can be reduced to a certain well-known game played by us all during boring classes! &lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113458625118544287?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113458625118544287/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113458625118544287&amp;isPopup=true' title='10 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113458625118544287'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113458625118544287'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/12/can-you-sum-me-out.html' title='Can you sum me out?'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>10</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113401793507334115</id><published>2005-12-07T20:13:00.000-08:00</published><updated>2005-12-07T21:13:22.300-08:00</updated><title type='text'>The figures of the Hindus...</title><content type='html'>This one is from the book &lt;span style="font-style: italic;"&gt;Liber Abaci&lt;/span&gt;, published in 1202. Authored by Leonardo Picano, as a compilation of all that he learned from his extensive travels, the book played a pivotal role in introducing Eastern knowledge into the (then) developing West. Because of the reputation of his father Bonacci (who was a state official), he sometimes took on the name of Leonardo Fibonacci (Fibonacci, from Latin &lt;span style="font-style: italic;"&gt;Filius bonacci &lt;/span&gt;meaning the progeny of Bonacci). Eight hundred years later, only his last name stuck, and today he is known as &lt;span style="font-weight: bold;"&gt;Fibonacci&lt;/span&gt;.&lt;br /&gt;&lt;br /&gt;The following puzzle from Fibonacci's book is a play on the "Hindu" decimal number system that he learnt in India:&lt;br /&gt;&lt;br /&gt;"A group of people are seated in a row, and one of them is wearing a ring on a certain joint of a certain finger. One person, who knows the whereabouts of the ring, computes a number as follows: He finds the wearer's position in the row, multiplies it by x, adds 5, multiplies that by z, and adds p. Then, he adds a number indicating the finger, and multiplies this by q. Then, he adds a number indicating the joint. When this number is announced, it is easy to pinpoint the ring. "&lt;br /&gt;&lt;br /&gt;Find x, z, p, q and tell me how to nail Frodo Baggins!&lt;br /&gt;&lt;br /&gt;(*) The problem is not that hard. You can assume that the joints in each finger are numbered 1 to 4. Further, a particular solution will suffice but make sure that you state the crucial logic. As usual, the first solution gets a point. But there is a bonus for the most elegant solution!&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113401793507334115?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113401793507334115/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113401793507334115&amp;isPopup=true' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113401793507334115'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113401793507334115'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/12/figures-of-hindus.html' title='The figures of the Hindus...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113356186110232186</id><published>2005-12-02T14:12:00.000-08:00</published><updated>2005-12-02T14:27:24.450-08:00</updated><title type='text'>Squarely solvable?</title><content type='html'>Consider N squares of sides 1, 2, 3...N. What is the minimum length of the square that will circumscribe all of these smaller squares?&lt;br /&gt;&lt;br /&gt;If you find that to be too easy, extend it to a circle!&lt;br /&gt;&lt;br /&gt;(No overlaps allowed)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113356186110232186?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113356186110232186/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113356186110232186&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113356186110232186'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113356186110232186'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/12/squarely-solvable_02.html' title='Squarely solvable?'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113313943643909750</id><published>2005-11-27T16:49:00.000-08:00</published><updated>2005-11-27T16:57:16.450-08:00</updated><title type='text'>An ancient Egyptian puzzle</title><content type='html'>An Arabic merchant willed that his 17 camels be divided amongst his 3 sons in the proportions 1/2, 1/3, and 1/9. You are a clever lawyer who is trusted to execute the will. How will you do it without slaughtering any animal?!&lt;br /&gt;&lt;br /&gt;(This one carries 1.5 points)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113313943643909750?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113313943643909750/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113313943643909750&amp;isPopup=true' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113313943643909750'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113313943643909750'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/11/ancient-egyptian-puzzle.html' title='An ancient Egyptian puzzle'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113218160758369887</id><published>2005-11-16T14:44:00.000-08:00</published><updated>2005-11-16T20:06:37.663-08:00</updated><title type='text'>Strange matrices from a dark auditorium...</title><content type='html'>Consider a matrix M, such that the sum of every row is the same as the sum of every column. That is, if you sum any row or column, it amounts to the same number. For example, with a sum of 18, M could be&lt;br /&gt;&lt;br /&gt;9       2     7&lt;br /&gt;4       6      8&lt;br /&gt;5     10     3&lt;br /&gt;&lt;br /&gt;Is it possible to construct a matrix M such that the sum of all its elements = 2^99 - 1?&lt;br /&gt;&lt;br /&gt;Original problem courtesy six hours of trecherous pain during a training session &lt;span style="font-style: italic;"&gt;a la &lt;/span&gt;the movie Office Space!&lt;br /&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;Note: Please include sisyphus' valid cribs in the comments section and the corrections concerning them...&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113218160758369887?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113218160758369887/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113218160758369887&amp;isPopup=true' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113218160758369887'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113218160758369887'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/11/strange-matrices-from-dark-auditorium.html' title='Strange matrices from a dark auditorium...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113193550746891045</id><published>2005-11-13T18:29:00.000-08:00</published><updated>2005-11-13T20:17:58.400-08:00</updated><title type='text'>Belt the answer out, if you can!</title><content type='html'>&lt;span style="color: rgb(0, 0, 0);"&gt; If a belt were placed around the Earth's equator, and then had six meters of length added to it, and you grabbed it at a point and lifted it until all the slack was gone, how high above Earth's surface would you be?&lt;br /&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;Note: This might sound like a very simple problem but&lt;/span&gt;...&lt;span style="font-style: italic;"&gt; &lt;/span&gt;:-)&lt;br /&gt;&lt;br /&gt;This is especially to counteract the disappointment of last problem!&lt;br /&gt;&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113193550746891045?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113193550746891045/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113193550746891045&amp;isPopup=true' title='14 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113193550746891045'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113193550746891045'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/11/belt-answer-out-if-you-can.html' title='Belt the answer out, if you can!'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>14</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113184373755347699</id><published>2005-11-12T16:53:00.000-08:00</published><updated>2005-11-12T17:05:44.363-08:00</updated><title type='text'>When do I take off?</title><content type='html'>You made millions in GOOG shares and is now the proud owner of a light aircraft to make your lunch trips from office to home (of course, home is situated on a hill overlooking the oceans in the distance and near a forest with ferns). While you are rich and smart, you still carry a peculiar grad student attribute much to your wife's annoyance: you dont find the necessity to lunch at any fixed time in the afternoon.&lt;br /&gt;&lt;br /&gt;It takes 15 minutes one way on a calm day without any wind and you spend 30 minutes at home to eat. Your house is due so&lt;br /&gt;uth of your airport (which adjoins your office). You notice that the wind always blows along the north-south axis throughout the year.&lt;br /&gt;&lt;br /&gt;All things being the same, the wind being the only variable, what should your strategy be to minimize the time of flight?&lt;br /&gt;&lt;br /&gt;ps: Wild shots are now accepted!&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113184373755347699?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113184373755347699/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113184373755347699&amp;isPopup=true' title='11 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113184373755347699'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113184373755347699'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/11/when-do-i-take-off.html' title='When do I take off?'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>11</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113177634522674924</id><published>2005-11-11T22:16:00.000-08:00</published><updated>2005-12-04T05:05:33.390-08:00</updated><title type='text'>A Lewis Carrol puzzle!</title><content type='html'>The White Queen tells the following riddle to Alice in &lt;i&gt;Through the Looking Glass. &lt;/i&gt;Lewis Carroll never answers it in the book. Let us see if you can!&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; 'First, the fish must be caught.'&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; That is easy: a baby, I think, could have&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; caught it.&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; 'Next, the fish must be bought.' That is easy: a penny, I think, would have&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; bought it.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; 'Now cook me the fish!'&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; That is easy, and will not take more than a minute.&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; 'Let it lie in a dish!'&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; That is easy, because it already is in it.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; 'Bring it here! Let me sup!'&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; It is easy to set such a dish on the table.&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; 'Take the dish-cover up!'&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; Ah, &lt;/span&gt;&lt;i style="color: rgb(255, 102, 102);"&gt;that&lt;/i&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; is so hard that I fear I'm unable!&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; For it holds like glue-&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; Holds the lid to the dish, while it lies in the&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; middle:&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; Which is easiest to do,&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; Un-dish-cover the fish, or dishcover the&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(255, 102, 102);"&gt; riddle?&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113177634522674924?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113177634522674924/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113177634522674924&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113177634522674924'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113177634522674924'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/11/lewis-carrol-puzzle.html' title='A Lewis Carrol puzzle!'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113088080839544244</id><published>2005-11-01T13:27:00.000-08:00</published><updated>2005-11-01T13:37:03.853-08:00</updated><title type='text'>Cold Calculations</title><content type='html'>Winter approaches and its time to face the snow in Minneapolis. As you turn on the morning news on your dark green Jaguar's radio as you leave for office (with a voice command of course), you hear the weather report.&lt;br /&gt;&lt;br /&gt;The snow begins to fall before 12:00pm and falls at a constant rate. Minneapolis sends out its first snow plow truck at noon and it begins removing snow at a constant rate (in cft/min). At 1.00 pm, it has gone 2 miles. At 2.00 pm, it has gone 3 miles, and is still not retracing its path. At what time did the snow start to fall?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113088080839544244?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113088080839544244/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113088080839544244&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113088080839544244'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113088080839544244'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/11/cold-calculations.html' title='Cold Calculations'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-113052223298998039</id><published>2005-10-28T10:56:00.000-07:00</published><updated>2005-10-28T10:57:12.990-07:00</updated><title type='text'>Party Shakers-2</title><content type='html'>Four couples attended a party. One couple was you and your spouse; another was Rama and Sita. Some people shook hands with one another, but nobody shook hands with oneself or with one's own spouse.&lt;br /&gt;&lt;br /&gt; After the party, you asked each person (except yourself) how many different people the person had shaken hands with. Each person replied with a different number--and each person's reply was truthful.&lt;br /&gt;&lt;br /&gt; You shook hands with Sita. Did your spouse shake hands with Sita? With Rama?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-113052223298998039?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/113052223298998039/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=113052223298998039&amp;isPopup=true' title='5 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113052223298998039'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/113052223298998039'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/party-shakers-2.html' title='Party Shakers-2'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>5</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112978143089353852</id><published>2005-10-19T21:04:00.000-07:00</published><updated>2005-10-19T21:10:30.893-07:00</updated><title type='text'>Bring a chessboard again..</title><content type='html'>Two small problems here...&lt;br /&gt;&lt;br /&gt;1. There are a number of squares on a chessboard. For instance,  any four or eight squares joined together form another big square. Count the total number of squares (all sizes).&lt;br /&gt;&lt;br /&gt;2. Considering boundaries of all 64 squares to be the roads, count the total number of routes you can take to traverse from one corner of a chess board to the diagonally opposite corner.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112978143089353852?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112978143089353852/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112978143089353852&amp;isPopup=true' title='11 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112978143089353852'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112978143089353852'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/bring-chessboard-again.html' title='Bring a chessboard again..'/><author><name>~A~</name><uri>http://www.blogger.com/profile/06939817730848411882</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>11</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112954823442026075</id><published>2005-10-17T04:10:00.000-07:00</published><updated>2005-10-17T04:32:25.020-07:00</updated><title type='text'>Lets play chess...</title><content type='html'>A knight is placed in one corner (the corner square, that is) of a chessboard. It moves in its own peculiar way and has to visit each square once and only once. Can it reach the diagonally opposite corner of the chessboard (again, the corner square at the diagonally opposite end)? If so, in how many moves?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112954823442026075?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112954823442026075/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112954823442026075&amp;isPopup=true' title='15 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112954823442026075'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112954823442026075'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/lets-play-chess.html' title='Lets play chess...'/><author><name>~A~</name><uri>http://www.blogger.com/profile/06939817730848411882</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>15</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112947690250557757</id><published>2005-10-16T08:31:00.000-07:00</published><updated>2005-10-16T08:35:02.516-07:00</updated><title type='text'>Humble Bicycle and friction</title><content type='html'>All of us have rode the bicylce at some point of time...and we all know that friction always opposes the motion.&lt;br /&gt;So, what is the direction of frictional forces on the front and rear wheel?&lt;br /&gt;  a) When pedalling&lt;br /&gt;  b) When idling (not pedalling).&lt;br /&gt;&lt;br /&gt;Source: This was a question from Resonance (an IISc publication for undegrads and grads) may be in he year 1998/97.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112947690250557757?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112947690250557757/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112947690250557757&amp;isPopup=true' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112947690250557757'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112947690250557757'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/humble-bicycle-and-friction.html' title='Humble Bicycle and friction'/><author><name>atma_tripta</name><uri>http://www.blogger.com/profile/13249144414026842896</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112922635478582942</id><published>2005-10-13T10:50:00.000-07:00</published><updated>2005-10-13T10:59:14.803-07:00</updated><title type='text'>Hey Water, Can I drink you?</title><content type='html'>The way we pollute water, me thinks thatone day we will all have to go to Mars to get some drinking water... So, NASA decides to send a spaceship to Mars to explore this possibility... The spaceship breaks the law of relativity using a loophole and reaches Mars within an Earth day. They reach Mars... find the frozen water in the lakes, take it to a region of 5 degrees C in Mars, melt it and then filter it. finally, to check safety of drinking it, he finds the pH which is close to 8. He goes on to check the chemical components of water thinking that there must be something basic in the water but finds it to be pure water. Explain the paradox.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112922635478582942?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112922635478582942/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112922635478582942&amp;isPopup=true' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112922635478582942'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112922635478582942'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/hey-water-can-i-drink-you.html' title='Hey Water, Can I drink you?'/><author><name>Born a Libran</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112888422273049188</id><published>2005-10-09T11:50:00.000-07:00</published><updated>2005-10-09T11:57:02.736-07:00</updated><title type='text'>Of sand mixtures and thermodynamics!</title><content type='html'>Hope you all are familiar with the common experience with haldiram bhujia...The big chunks of the yummy stuff is always on the top and separates out from the rest of the smaller sized bhujia.  I say this because, we always had a fight at home as to who gets to open the pack! Similarly...if you shake a mixture of sand, you will find the bigger sized stones always on top.&lt;br /&gt;&lt;br /&gt;Now the question is: Since shaking is a random process,  we should expect the particles to be randomly distributed (to have more disorder, increase in entropy) but we have an apparent order (separation of particles into different sizes).  Isn't it a against our second law of thermodynamics? Where is the catch? :)&lt;br /&gt;@&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112888422273049188?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112888422273049188/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112888422273049188&amp;isPopup=true' title='8 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112888422273049188'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112888422273049188'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/of-sand-mixtures-and-thermodynamics.html' title='Of sand mixtures and thermodynamics!'/><author><name>atma_tripta</name><uri>http://www.blogger.com/profile/13249144414026842896</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>8</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112869669780535533</id><published>2005-10-07T07:49:00.000-07:00</published><updated>2005-10-07T07:51:37.806-07:00</updated><title type='text'>Party shakers...</title><content type='html'>In any party, there is a lot of handshaking. Show that there are atleast two people who have shaken hands with an equal number of people. &lt;br /&gt;&lt;br /&gt;(credits:tuku)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112869669780535533?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112869669780535533/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112869669780535533&amp;isPopup=true' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112869669780535533'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112869669780535533'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/party-shakers.html' title='Party shakers...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112857217135134702</id><published>2005-10-05T21:12:00.000-07:00</published><updated>2005-10-06T20:18:33.136-07:00</updated><title type='text'>The clank of the little kids...</title><content type='html'>You walk into a school with 100 kids all of which are hyperactive. The school has 100 lockers one for each numbered from 1 to 100. The first kid walks into the locker room and opens all of them. The second kid zooms past and changes the status of every even numbered locker. The third kid waltzes through the room changing the status of lockers divisible by 3 (3,6,9 etc.), the fourth one does the same with all that is divisible by 4 and they do the closing and opening alternately. Which lockers are open at the end of the day? And what's your logic?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112857217135134702?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112857217135134702/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112857217135134702&amp;isPopup=true' title='13 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112857217135134702'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112857217135134702'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/10/clank-of-little-kids.html' title='The clank of the little kids...'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>13</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112812786194472140</id><published>2005-09-30T17:46:00.000-07:00</published><updated>2005-09-30T17:51:01.950-07:00</updated><title type='text'>Making roads</title><content type='html'>You are an engineer in the middle of a small and beautiful village with mountains looming in the background. They have a mud road and insist on building another thats perfectly perpendicular to the first one. Skanda's house is on the original road and the new road intersects in front of his house. Like all spirited people, they want to test your college education and give you a long rope. How do you find the right angle?&lt;br /&gt;&lt;br /&gt;In other words, given a long rope, how can you fold it into a right-angled triangle? &lt;br /&gt;&lt;br /&gt;I am tempted to give you a hint but GOD, someone please attempt a solution... :-)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112812786194472140?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112812786194472140/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112812786194472140&amp;isPopup=true' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112812786194472140'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112812786194472140'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/09/making-roads.html' title='Making roads'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-15947468.post-112697703271790269</id><published>2005-09-17T10:09:00.000-07:00</published><updated>2005-09-17T10:10:32.716-07:00</updated><title type='text'>Power balance</title><content type='html'>A chess board has 64 squares. Pick numbers between 1 and 64 and place these numbers on each of the squares of the chess board such that the value in every square is the average of the values of its neighboring squares. &lt;br /&gt;&lt;br /&gt;Prove that the only way to make such an arrangement is when all squares have equal numbers. &lt;br /&gt;&lt;br /&gt;(http://www.cisl.columbia.edu/grads/tuku/brainteasers.html)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/15947468-112697703271790269?l=xyfactor.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://xyfactor.blogspot.com/feeds/112697703271790269/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=15947468&amp;postID=112697703271790269&amp;isPopup=true' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112697703271790269'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/15947468/posts/default/112697703271790269'/><link rel='alternate' type='text/html' href='http://xyfactor.blogspot.com/2005/09/power-balance.html' title='Power balance'/><author><name>littlecow</name><uri>http://www.blogger.com/profile/12137446631889343916</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>3</thr:total></entry></feed>
