Tuesday, July 18, 2006

Angles of a Quadrilateral

Simple Question

a) What is the minimum number of acute angles in a convex quadrilateral? Prove.

That may be too easy. So, I'll give a point to (or split point between) the most creative and entertaining answer(s).

b) What is the minimum number of acute angles in a concave quadrilateral? Prove.

Clarification:

By acute, I mean angles that are 90 deg or lower. Acute = Non-obtuse.

5 Comments:

Blogger Rajagopal said...

1) Convex - minimum 0. All four angles can be 90 deg and so none of the angles needs to be obtuse.

2) Concave - 2. Atleast one angle is more than 180 deg and sum of other three angles is less than 180. So even if one of the other three angles is obtuse (>90), the remaining two have to be acute.

So atleast 2 angles of a convex quad. should be acute.

Tue Jul 18, 09:42:00 PM 2006  
Anonymous Anonymous said...

w+x+y+z=360,
I.
Let us assume w,x,y are all in (90,180)
=> (w+x+y) is in (270,540)
=> z can lie in (0,90)
Thus minimum no of acute angles in a convex quad. is ONE.

II.
Let w be the reflex angle.
=>w lies in (180,360)
=>x+y+z lies in (0,180)
Thus,there cannot be two obtuse angles in x,y or z simultaneously.
Thus in a concave quad., the minimum no. of acute angles is TWO.

BTW,long time between puzzles,eh?

Thu Jul 20, 10:06:00 AM 2006  
Blogger Sisyphus said...

Raju and Sai did not read my clarification (which I posted along with the question). So, no points for you.

Grenade has invented a better problem and provided a satisfying answer.

Oh Blogmaster, the great littlecow, could you give a point to Grenade?!

Thanks.

Wed Sep 27, 10:47:00 PM 2006  
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